Two slots and a flange to a traditional conical hood opening. Three plates were designed to change the geometry of a plain conical hood (slot area: 0.1334, 0.0963 and 0.0694 ft. They were tested at different airflow rates (243, 347, 467, 647, 897 cubic feet per minute) for a set number of distances from the hood face using a thermal. The slots cause the water to raise up and accelerate through the smaller openings which creates a suction force that pulls material in better. And 30' of overflow is more than enough for 1,500gph. #5 rbarn, Oct 20, 2013. Answer to Characterizing Flow Rates (§5.1) The rectangular channel shown is 1.2 m wide. What is the discharge in the channel?.
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vol flow | mass flow | flow speed | vol | mass | time |
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w x h | flow speed | vol flow | |||
time | vol | mass | vol flow | mass flow | |
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mass | time | density | mass flow | ||
density | mass flow | vol flow | mass | vol | |
flow speed | area, dia |
This tool will calculate the volumetric flow rate in any units from the specified velocity of a substance flowing through a defined cross-sectional area. For each new calculation a unique conversion scale will be generated for the range of flow velocities and volumetric flow rates with the cross sectional area specified.
The volumetric flow rate formula used by this calculator is:
Q = v · A
n.b. This formula assumes uniform flow conditions within the entire cross-sectional area, without any friction losses near to surfaces.
Enter the speed at which the substance is moving.
Enter the size of the area perpendicular to the direction of flow.
This is the amount of volume that will flow pass per unit of time.